IOE track

IOE Entrance preparation

Crack Pulchowk and TU engineering entrance with adaptive practice across Physics, Math, Chemistry and English. Full-length mocks tuned to the IOE pattern.

Free track available
Questions

12,400+

Mock exams

60+

Built for

+2 Science graduates

What you get on MakerHub

  • Timed practice by chapter
  • Exam sets with question navigator
  • Post-mock Maven coach per question
  • Topic accuracy dashboard

Syllabus coverage

Structured practice and mocks aligned to IOE section weights.

Physics

35%
MechanicsElectromagnetismOpticsModern Physics

Mathematics

35%
AlgebraCalculusTrigonometryVectorsStatistics

Chemistry

20%
PhysicalInorganicOrganic

English

10%
GrammarComprehensionVocabulary

Frequently asked questions

What is the IOE entrance exam pattern?

IOE entrance consists of 100 MCQs from Physics (35%), Mathematics (35%), Chemistry (20%), and English (10%). The exam is 2 hours long with no negative marking.

How many students appear for IOE entrance each year?

Approximately 15,000–20,000 students appear for IOE entrance annually, competing for around 1,200 seats across Pulchowk, Thapathali, Paschimanchal, and other TU engineering campuses.

What is the cutoff for Pulchowk Campus?

Pulchowk Campus typically requires a rank within the top 300–400. The exact cutoff varies yearly based on exam difficulty and seat availability.

Is calculator allowed in IOE entrance?

No, calculators are not allowed in IOE entrance. Students must perform calculations manually. Practice mental math and approximation techniques.

How to prepare for IOE physics effectively?

Focus on mechanics, electromagnetism, and optics as these carry maximum weight. Practice numerical problems daily and understand concepts rather than memorizing formulas.

Sample question

A body is projected horizontally from a height of 20 m with a velocity of 10 m/s. The time taken to reach the ground is approximately (g = 10 m/s²)

1 s
2 s
3 s
4 s

Explanation

For horizontal projection, vertical motion is independent: h = ½gt². So 20 = ½·10·t² ⇒ t² = 4 ⇒ t = 2 s.

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